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String Spacing Calculator

Calculator

Parameters

String gauges

From bass side to treble side, in thousands of an inch

How it works

Applications

Most guitars have strings spaced so that the gap between each string is the same. Since each string has a different gauge (thickness), this means that the center of the strings are not equidistant.

This calculation applies along the full length of the strings, from the nut to the bridge. It is typically used for calculating the position of the nut slots, but can also be used for slotting a bridge if needed.

Formula

To calculate the position of each nut slot, we need to take into account:
  • WW = width of the nut (edge to edge) - in mm
  • DED_E = distance from the edge of the E string to the edge of the nut on the bass side (in mm)
  • DeD_e = distance from the edge of the e string to the edge of the nut on the treble side (in mm)
  • NN = the number of strings
  • GG = the gauge of all the strings combined. We typically measure this in thousands of an inch, since that's the unit used by most string manufacturers, but for the calculation we'll convert it to millimeters. For example if my gauges are 9, 11, 16, 26, 36, 46, GG would be the sum which is 0.154", or 3.91mm.

Based on this, we can calculate what the distance between each string DD should be so that it is the same between each string. It will be equal to the width of the nut WW minus the space taken by the strings GG minus the space on each side of the nut DE+DeD_E + D_e, divided by the number of gaps between strings which is N1N-1.

D=WDEDeGN1D = \cfrac{W - D_E - D_e - G}{N-1}

This gives us the distance between the edge of each string. Based on that, the gauge of each string and the distance to each edge of the nut, the position of the center of each string can be calculated, which will be where the nut slots should be.

Example

If we use the formula with the following parameters that are pretty standard for an electric guitar:
  • W=44W = 44 mm
  • DE=3D_E = 3 mm
  • De=3D_e = 3 mm
  • N=6N = 6 strings
  • G=3.91G = 3.91 mm (0.154", sum of 9, 11, 16, 26, 36, 46 gauges)

then we get:

D=44333.915D = \cfrac{44 - 3 - 3 - 3.91}{5}
D=6.818mmD = 6.818 mm

The edge of each string will be 6.818mm apart from each other.